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H3CSE-RS-RT Sample Questions:

1. RTA 与 RTB , RTC , RTD 建立了 IBGP 对等体关系。 RTA 在向这三个 IBGP 对等体发布路由时候使用统一的过滤器 3001 ,通过 peer group 实现。
为实现如上目的,管理员在 RTA 上配置如下 :
[RTA-BGP] group in internal
[RTA-BGP] peer in connect-interface Loopback0
[RTA-BGP] peer 10.0.0.2 group in
[RTA-BGP] peer 10.0.0.3 group in
[RTA-BGP] peer 10.0.0.4 group in
[RTA-BGP] peer in filter-polic3001
则上述配置语句中,错误的是

A) [RTA-BGP] peer in connect-interface Loopback0
B) [RTA-BGP] peer 10.0.0.2 group in [RTA-BGP] peer 10.0.0.3 group in [RTA-BGP] peer 10.0.0.4 group in
C) [RTA-BGP] group in internal
D) [RTA-BGP] peer in filter-polic3001

2. 在图示各种路由器建立 IS-IS 邻居关系后,发送过 CSNP 消息的路由器有。

A) [RTA
B) [RTC
C) RTD
D) [RTB

3. 在图示网络中 , 各路由器间 BGP 路由学习正常 , BGP 路由属性都去缺省值。

在 RTA 上将路由 100.10.1.0/24 引入 BGP 中后, RTD 的 BGP 路由表中 100.10.1.0/24 的下一跳是 ?

A) RTB
B) RTA
C) RTE
D) RTC

4. 关于 OSPF 中的第一类外部路由和第二类外部路由,一下说法正确的是

A) 第一类外部路由都是注入 IGP 路由产生的
B) 第一类外部路由都是注入 BGP 路由产生的
C) 同一网段的路由信息,如果同时通过第一类外部路由和第二类外部路由学习到,在其他条件相同的情况下,会优选第一类外部路由信息
D) 默认情况下,通过其他路由协议引入到 OSPF 协议中的路由都是第二类外部路由

5. 在如图所示的拓扑中, RTA 、 RTB 、 RTC 和 RTD 上分别执行如下配置 :

[RTA-LoopBack0] ip address 1.1.1.1 255.255.255.255
[RTA] ospf 1
[RTA-ospf-1] area 1
[RTA-ospf-1-area-0.0.0.1] network 10.0.0.0 0.0.0.255
[RTA-ospf-1] import-route direct
[RTB-LoopBack0] ip address 2.2.2.2 255.255.255.255
[RTB] ospf 1
[RTB-ospf-1] area 1
[RTB-ospf-1-area-0.0.0.1] network 10.0.0.0 0.0.0.255
[RTB-ospf-1-area-0.0.0.1] area 0
[RTB-ospf-1-area-0.0.0.0] network 2.2.2.2 0.0.0.0
[RTB-ospf-1-area-0.0.0.0] network 20.0.0.0 0.0.0.255
[RTC-LoopBack0] ip address 3.3.3.3 255.255.255.255
[RTC] ospf 1
[RTC-ospf-1] area 0
[RTC-ospf-1-area-0.0.0.0] network 20.0.0.0 0.0.0.255
[RTC-ospf-1-area-0.0.0.0] area 2
[RTC-ospf-1-area-0.0.0.2] nssa no-import-route no-summar
[RTC-ospf-1-area-0.0.0.2] network 30.0.0.0 0.0.0.255
[RTC-ospf-1] import-route direct
[RTD-LoopBack0] ip address 4.4.4.4 255.255.255.255
[RTD] ospf 1
[RTD-ospf-1] area 2
[RTD-ospf-1-area-0.0.0.2] network 30.0.0.0 0.0.0.255
[RTD-ospf-1-area-0.0.0.2] network 4.4.4.4 0.0.0.0
[RTD-ospf-1-area-0.0.0.2] nssa
则骨干区域中可能注入

A) Tpe3 LSA
B) Tpe4 LSA
C) Tpe7 LSA
D) Tpe5 LSA

Solutions: